![]() Then that byte value is sent as a hexadecimal string of 2 characters. when applicable), truncated to the least significant byte. The calculation is 0x55 - command byte - vreg byte 1 - vreg byte 2 - flags byte (- data byte 1 - data byte 2. The checksum is always 1 byte that is calculated using the other byte values. ![]() So a command value of 0x7 is transmitted as the "7". The 0圎D hex editor was used to make this hack. The command is a an exception in the sense that it is treated as a regular byte for the checksum calculation, but only the lowest nibble (which is 4 bits) is sent, so this means only 1 character of the hexadecimal string. Description: This hack restores all the red blood that was removed from the American version back to it, it also decensors the game’s script as well. The flags are a byte, and when they have the value 0x00, they are transmitted as "00". Two hexadecimal characters contained in each eight- bit field of the message. The vreg id is 0圎DF0, which is 2 bytes with the values 0xF0 and 0圎D in little endian format and thus is transmitted as "F0ED". The data that is transmitted are byte values printed as a hexadecimal number (printf("%02X", byte_value) in C). It seems you are doing the calculation using the ascii character representations of the hex numbers: ![]() When you receive an answer, the flags can have a different value. When sending things to a product, the flags should be 0. 0圎B hex to dec 0d235 dec 0圎C hex to dec 0d236 dec 0圎D hex to dec. I understand why I have to convert, but why don't I use both nibbles? Convert 0圎3 hexadecimal to decimal, hex to dec unit converter with conversion. When I do your calculation, I get a negative number of -399 decimal, and then I convert it to signed hex and I get 0xFE71. Why am I converting the hex numbers into ascii representations of those numbers? I would have done the following calculation:Ġx55-0x37-0x46-0x30-0x44-0x45 = checksum, and I get an answer of 0xFF1F. It seems you are doing the calculation using the ascii character representations of the hex numbers. The calculation is 0x55 minus the command and the data bytes. The calculation of the checksum is repeatable, but still not clear to me. I can't find this in the protocol manual, but I will just remember to use it. This code works, but I'd like to understand better how you got to this answer, because it is still vague to me.Īll flags on all commands are going to be represented as 30 30, which correspond to ascii 0 0.
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